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TiddlyWiki5/editions/test/tiddlers/tests/test-linked-list.js

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/*\
title: test-linked-list.js
type: application/javascript
tags: [[$:/tags/test-spec]]
Tests the utils.LinkedList class.
LinkedList was built to behave exactly as $tw.utils.pushTop and
Array.prototype.push would behave with an array.
Many of these tests function by performing operations on a paired set of
an array and LinkedList. It uses equivalent actions on both.
Then we confirm that the two come out functionally identical.
NOTE TO FURTHER LINKED LIST DEVELOPERS:
If you want to add new functionality, like 'shift' or 'unshift', you'll
probably need to deal with the fact that Linked List will insert undefined
as a first entry into an item's 'prev' array when it's at the front of
the list, but it doesn't do the same for the 'next' array when it's at
the end. I think you'll probably be better off preventing 'prev' from ever
adding undefined.
\*/
(function(){
/*jslint node: true, browser: true */
/*global $tw: false */
"use strict";
describe("LinkedList class tests", function() {
// creates and initializes a new {array, list} pair for testing
function newPair(initialArray) {
var pair = {array: [], list: new $tw.utils.LinkedList()};
if (initialArray) {
push(pair, initialArray);
}
return pair;
};
// pushTops a value or array of values into both the array and linked list.
function pushTop(pair, valueOrValues) {
pair.list.pushTop(valueOrValues);
$tw.utils.pushTop(pair.array, valueOrValues);
return pair;
};
// pushes values into both the array and the linked list.
function push(pair, values) {
pair.list.push(values);
pair.array.push.apply(pair.array, values);
return pair;
};
// operates a remove action on an array and a linked list in parallel.
function remove(pair, valueOrValues) {
pair.list.remove(valueOrValues);
$tw.utils.removeArrayEntries(pair.array, valueOrValues);
return pair;
};
// This returns an array in reverse using a LinkList's prev member. Thus
// testing that prev is not corrupt. It doesn't exist in the LinkList module
// itself to avoid full support for it. Maybe that will change later.
function toReverseArray(list) {
var visits = Object.create(null),
value = list.prev.get(null),
array = [];
while(value !== null) {
array.push(value);
var prev = list.prev.get(value);
if(Array.isArray(prev)) {
var i = (visits[value] || prev.length) - 1;
visits[value] = i;
value = prev[i];
} else {
value = prev;
}
}
return array;
};
// compares an array and a linked list to make sure they match up
function compare(pair) {
var forward = pair.list.toArray();
expect(forward).toEqual(pair.array);
expect(pair.list.length).toBe(pair.array.length);
// Now we reverse the linked list and test it back to front, thus
// confirming that the list.prev isn't corrupt.
expect(toReverseArray(pair.list)).toEqual(forward.reverse());
return pair;
};
it("can pushTop", function() {
var pair = newPair(["A", "B", "C"]);
// singles
pushTop(pair, "X");
pushTop(pair, "B");
compare(pair); // ACXB
//arrays
pushTop(pair, ["X", "A", "G", "A"]);
// If the pushedTopped list has duplicates, they go in unempeded.
compare(pair); // CBXAGA
});
it("can pushTop with tricky duplicates", function() {
var pair = newPair(["A", "B", "A", "C", "A", "e"]);
// If the original list contains duplicates, only one instance is cut
compare(pushTop(pair, "A")); // BACAeA
// And the Llist properly knows the next 'A' to cut if pushed again
compare(pushTop(pair, ["X", "A"])); // BCAeAXA
// One last time, to make sure we maintain the linked chain of copies
compare(pushTop(pair, "A")); // BCeAXAA
});
it("can pushTop a single-value list with itself", function() {
// This simple case actually requires special handling in LinkedList.
compare(pushTop(newPair(["A"]), "A")); // A
});
it("can remove all instances of a multi-instance value", function() {
var pair = compare(remove(newPair(["A", "A"]), ["A", "A"])); //
// Now add 'A' back in, since internally it might be using arrays,
// even though those arrays must be empty.
compare(pushTop(pair, "A")); // A
// Same idea, but push something else before readding 'A'
compare(pushTop(remove(newPair(["A", "A"]), ["A", "A"]), ["B", "A"])); // BA
// Again, but this time with other values mixed in
compare(remove(newPair(["B", "A", "A", "C"]), ["A", "A"])) // BC;
// And again, but this time with value inbetween too.
compare(remove(newPair(["B", "A", "X", "Y", "Z", "A", "C"]), ["A", "A"])); // BXYZC
// One last test, where removing a pair from the end could corrupt
// list.last.
pair = remove(newPair(["D", "C", "A", "A"]), ["A", "A"]);
// But I can't figure out another way to test this. It's wrong
// for list.last to be anything other than a string, but I
// can't figure out how to make that corruption manifest a problem.
// So I dig into its private members. Bleh...
expect(typeof pair.list.prev.get(null)).toBe("string");
});
it("can pushTop value linked to by a repeat item", function() {
var pair = newPair(["A", "B", "A", "C", "A", "C", "D"]);
// This is tricky because that 'C' is referenced by a second 'A'
// It WAS a crash before
pushTop(pair, "C");
compare(pair); // ABAACDC
});
it("can pushTop last value after pair", function() {
// The 'next' ptrs for A would be polluted with an extraneous
// undefined after the pop, which would make pushing the 'X'
// back on problematic.
compare(pushTop(newPair(["A", "A", "X"]), "X")); // AACX
// And lets try a few other manipulations around pairs
compare(pushTop(newPair(["A", "A", "X", "C"]), "X")); // AACX
compare(pushTop(newPair(["X", "A", "A"]), "X")); // AAX
compare(pushTop(newPair(["C", "X", "A", "A"]), "X")); // CAAX
});
it("can remove all instances of a multi-instance value #7059", function() {
// Remove duplicate items when one or more items between the duplicates
// are not removed and the first of those duplicates is not the first item.
// These tests used to fail prior to the fix to #7059
compare(remove(newPair(["A", "A", "C", "B", "A"]), ["A", "C", "A", "A"])); // B
compare(remove(newPair(["A", "A", "C", "B", "A"]), ["C", "A", "A", "A"])); // B
compare(remove(newPair(["A", "A", "C", "B", "A"]), ["A", "A", "A"])); // CB
compare(remove(newPair(["A", "A", "C", "B", "A"]), ["A", "A", "A", "C"])); // B
compare(remove(newPair(["A", "A", "B", "A"]), ["A", "A", "A"])); // B
compare(remove(newPair(["A", "A", "B", "A"]), ["A", "A", "A", "B"])); //
compare(remove(newPair(["C", "A", "B", "A"]), ["C", "A", "A"])); // B
compare(remove(newPair(["C", "A", "B", "A", "C"]), ["C", "A", "A", "C"])); // B
compare(remove(newPair(["B", "A", "B", "A"]), ["B", "A", "A"])); // B
});
it("can handle particularly nasty pushTop pitfall", function() {
var pair = newPair(["A", "B", "A", "C"]);
pushTop(pair, "A"); // BACA
pushTop(pair, "X"); // BACAX
remove(pair, "A"); // BCAX
pushTop(pair, "A"); // BCXA
remove(pair, "A"); // BCX
// But! The way I initially coded the copy chains, a mystery A could
// hang around.
compare(pair); // BCX
});
it("can handle past-duplicate items when pushing", function() {
var pair = newPair(["X", "Y", "A", "C", "A"]);
// Removing an item, when it has a duplicat at the list's end
remove(pair, "A");
compare(pair); // XYCA
// This actually caused an infinite loop once. So important test here.
push(pair, ["A"]);
compare(pair); // XYCAA
pushTop(pair, "A") // switch those last As
compare(pair); // XYCAA
remove(pair, ["A", "A"]); // Remove all As, then add them back
pushTop(pair, ["A", "A"])
compare(pair); // XYCAA
});
it("can push", function() {
var list = new $tw.utils.LinkedList();
// singles
expect(list.push("A")).toBe(1);
expect(list.push("B")).toBe(2);
// multiple args
expect(list.push("C", "D", "E")).toBe(5);
// array arg allowed
expect(list.push(["F", "G"])).toBe(7);
// No-op
expect(list.push()).toBe(7);
expect(list.toArray()).toEqual(["A", "B", "C", "D", "E", "F", "G"]);
});
it("can handle empty string", function() {
compare(newPair(["", "", ""])); // ___
compare(push(newPair([""]), [""])); // __
compare(pushTop(newPair(["", "", ""]), ["A", ""])); // __A_
compare(remove(newPair(["", "A"]), "A")); // _
compare(push(newPair(["", "A"]), ["A"])); // _AA
compare(remove(newPair(["A", ""]), "A")); // _
compare(push(newPair(["A", ""]), ["A"])); // A_A
// This one is tricky but precise. Remove 'B', and 'A' might mistake
// it as being first in the list since it's before ''. 'C' would get
// blasted from A's prev reference array.
compare(remove(newPair(["C", "A", "", "B", "A"]), ["B", "A"])); // C_A
// Same idea, but with A mistaking B for being at the list's end, and
// thus removing C from its 'next' reference array.
compare(remove(newPair(["A", "B", "", "A", "C"]), ["B", "A"])); // _AC
});
it("will throw if told to push non-strings", function() {
var message = "Linked List only accepts string values, not ";
var list = new $tw.utils.LinkedList();
expect(() => list.push(undefined)).toThrow(message + "undefined");
expect(() => list.pushTop(undefined)).toThrow(message + "undefined");
expect(() => list.pushTop(["c", undefined])).toThrow(message + "undefined");
expect(() => list.pushTop(5)).toThrow(message + "5");
expect(() => list.pushTop(null)).toThrow(message + "null");
// now lets do a quick test to make sure this exception
// doesn't leave any side-effects
// A.K.A Strong guarantee
var pair = newPair(["A", "5", "B", "C"]);
expect(() => pushTop(pair, 5)).toThrow(message + "5");
compare(pair);
expect(() => push(pair, ["D", 7])).toThrow(message + "7");
compare(pair);
expect(() => remove(pair, 5)).toThrow(message + "5");
compare(pair);
// This is the tricky one. 'A' and 'B' should not be removed or pushed.
expect(() => pushTop(pair, ["A", "B", null])).toThrow(message + "null");
compare(pair);
expect(() => remove(pair, ["A", "B", null])).toThrow(message + "null");
compare(pair);
});
it("can clear", function() {
var list = new $tw.utils.LinkedList();
list.push("A", "B", "C");
list.clear();
expect(list.toArray()).toEqual([]);
expect(list.length).toBe(0);
});
it("can remove", function() {
var list = new $tw.utils.LinkedList();
list.push(["A", "x", "C", "x", "D", "x", "E", "x"]);
// single
list.remove("x");
// arrays
list.remove(["x", "A", "XXX", "x"]);
expect(list.toArray()).toEqual(["C", "D", "E", "x"]);
});
it("can ignore removal of nonexistent items", function() {
var pair = newPair(["A", "B", "C", "D"]);
// single
compare(remove(pair, "Z")); // ABCD
// array
compare(remove(pair, ["Z", "B", "X"])); // ACD
});
it("can iterate with each", function() {
var list = new $tw.utils.LinkedList();
list.push("0", "1", "2", "3");
var counter = 0;
list.each(function(value) {
expect(value).toBe(counter.toString());
counter = counter + 1;
});
expect(counter).toBe(4);
});
it("can iterate a list of the same item", function() {
// Seems simple. Caused an infinite loop during development.
compare(newPair(["A", "A"]));
});
});
})();