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calibre-web/cps/pagination.py
2021-10-04 19:23:24 +02:00

76 lines
2.9 KiB
Python

# -*- coding: utf-8 -*-
# This file is part of the Calibre-Web (https://github.com/janeczku/calibre-web)
# Copyright (C) 2018-2019 OzzieIsaacs, cervinko, jkrehm, bodybybuddha, ok11,
# andy29485, idalin, Kyosfonica, wuqi, Kennyl, lemmsh,
# falgh1, grunjol, csitko, ytils, xybydy, trasba, vrabe,
# ruben-herold, marblepebble, JackED42, SiphonSquirrel,
# apetresc, nanu-c, mutschler
#
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program. If not, see <http://www.gnu.org/licenses/>.
from math import ceil
# simple pagination for the feed
class Pagination(object):
def __init__(self, page, per_page, total_count):
self.page = int(page)
self.per_page = int(per_page)
self.total_count = int(total_count)
@property
def next_offset(self):
return int(self.page * self.per_page)
@property
def previous_offset(self):
return int((self.page - 2) * self.per_page)
@property
def last_offset(self):
last = int(self.total_count) - int(self.per_page)
if last < 0:
last = 0
return int(last)
@property
def pages(self):
return int(ceil(self.total_count / float(self.per_page)))
@property
def has_prev(self):
return self.page > 1
@property
def has_next(self):
return self.page < self.pages
# right_edge: last right_edges count of all pages are shown as number, means, if 10 pages are paginated -> 9,10 shwn
# left_edge: first left_edges count of all pages are shown as number -> 1,2 shwn
# left_current: left_current count below current page are shown as number, means if current page 5 -> 3,4 shwn
# left_current: right_current count above current page are shown as number, means if current page 5 -> 6,7 shwn
def iter_pages(self, left_edge=2, left_current=2,
right_current=4, right_edge=2):
last = 0
left_current = self.page - left_current - 1
right_current = self.page + right_current + 1
right_edge = self.pages - right_edge
for num in range(1, (self.pages + 1)):
if num <= left_edge or (left_current < num < right_current) or num > right_edge:
if last + 1 != num:
yield None
yield num
last = num