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Code Issues Releases Wiki Activity

Slightly speed up [all[shadows+tiddlers]] filters (#7702)

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The `all` filter operator has shortcuts to optimise common patterns like
`[all[shadows+tiddlers]]` or `[all[tiddlers]]`. In those cases, the
filter operator function returns early and never uses the `result`
linked list that was created, so it's immediately garbage-collected.
Let's delay creating it until we know it's actually going to be used.
This commit is contained in:
Robin Munn 2023-09-25 02:19:04 +07:00 committed by GitHub
parent 526e997aa4
commit 780e5d33a4
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GPG Key ID: 4AEE18F83AFDEB23
1 changed files with 5 additions and 5 deletions
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10
core/modules/filters/all.js
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@ -28,12 +28,8 @@ function getAllFilterOperators() {
Export our filter function
*/
exports.all = function(source,operator,options) {
// Get our suboperators
var allFilterOperators = getAllFilterOperators();
// Cycle through the suboperators accumulating their results
var results = new $tw.utils.LinkedList(),
subops = operator.operand.split("+");
// Check for common optimisations
var subops = operator.operand.split("+");
if(subops.length === 1 && subops[0] === "") {
return source;
} else if(subops.length === 1 && subops[0] === "tiddlers") {
@ -46,6 +42,10 @@ exports.all = function(source,operator,options) {
return options.wiki.eachShadowPlusTiddlers;
}
// Do it the hard way
// Get our suboperators
var allFilterOperators = getAllFilterOperators();
// Cycle through the suboperators accumulating their results
var results = new $tw.utils.LinkedList();
for(var t=0; t<subops.length; t++) {
var subop = allFilterOperators[subops[t]];
if(subop) {